• Jan 8, 2026 vectors and projectiles packet answers packet 3 multaneously, a current flows with a velocity of 2 m/s directly north. Find the resultant velocity of the swimmer and the direction. Solution: Resultant velocity (V): \[ V = \sqrt{V_x^2 + V_y^2} = \sqrt{3^2 + 2^2} = \sqrt{9 + 4} = \sqrt{13} \approx 3.61 By Alexandra Dickens
